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(D) The hydrides of the given elements are:$NaH$ (Sodium hydride)$H_2O$ (Water)$BH_3$ (Borane)$SiH_4$ (Silane)Comparing the number of hydrogen atoms p

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$Si$

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(D) The hydrides of the given elements are:$NaH$ (Sodium hydride)$H_2O$ (Water)$BH_3$ (Borane)$SiH_4$ (Silane)Comparing the number of hydrogen atoms per atom of the element:For $NaH$,ratio is $1:1$.For $H_2O$,ratio is $2:1$.For $BH_3$,ratio is $3:1$.For $SiH_4$,ratio is $4:1$.Thus,$Si$ forms a hydride with the maximum number of hydrogen atoms per atom of the element.

The element whose hydride contains the maximum number of hydrogen atoms per atom of the element is

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