The element with outer electronic configurati | vedclass

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Question

(B) The given electronic configuration is $(n-1)d^2 ns^2$ with $n=4$.Since the principal quantum number $n$ represents the period number,the element b

Vedclass · Accepted Answer

$4^{	ext{th}}$ period,$4^{	ext{th}}$ group

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(B) The given electronic configuration is $(n-1)d^2 ns^2$ with $n=4$.Since the principal quantum number $n$ represents the period number,the element belongs to the $4^{	ext{th}}$ period.For $d$-block elements,the group number is calculated as the sum of electrons in the $(n-1)d$ subshell and the $ns$ subshell.Group number = (Number of electrons in $(n-1)d$) + (Number of electrons in $ns$) = $2 + 2 = 4$.Therefore,the element belongs to the $4^{	ext{th}}$ period and $4^{	ext{th}}$ group.

Temporary Systematic Name	$IUPAC$ Official Name
$a$. Unnilunium $(101)$	$i$. Mendelevium $(Md)$
$b$. Unniltrium $(103)$	$ii$. Lawrencium $(Lr)$
$c$. Unnilhexium $(106)$	$iii$. Seaborgium $(Sg)$
$d$. Ununnilium $(110)$	$iv$. Darmstadtium $(Ds)$

The element with outer electronic configuration $(n-1)d^2 ns^2$,where $n=4$,would belong to

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Identify the incorrect match :

Temporary Systematic Name $IUPAC$ Official Name

$a$. Unnilunium $(101)$ $i$. Mendelevium $(Md)$

$b$. Unniltrium $(103)$ $ii$. Lawrencium $(Lr)$

$c$. Unnilhexium $(106)$ $iii$. Seaborgium $(Sg)$

$d$. Ununnilium $(110)$ $iv$. Darmstadtium $(Ds)$

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