The element with the electronic configuration | vedclass

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Question

(B) The atomic number of $Kr$ (Krypton) is $36$. The total number of electrons in the given configuration $[Kr] \ 4d^{10} \ 5s^0$ is $36 + 10 + 0 = 46

Vedclass · Accepted Answer

$Pd$

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(B) The atomic number of $Kr$ (Krypton) is $36$. The total number of electrons in the given configuration $[Kr] \ 4d^{10} \ 5s^0$ is $36 + 10 + 0 = 46$.The element with atomic number $46$ is Palladium $(Pd)$.According to the provided data:- $Ag$ $(Z=47)$: $[Kr] \ 4d^{10} \ 5s^1$- $Pd$ $(Z=46)$: $[Kr] \ 4d^{10} \ 5s^0$- $Rh$ $(Z=45)$: $[Kr] \ 4d^8 \ 5s^1$- $Tc$ $(Z=43)$: $[Kr] \ 4d^5 \ 5s^2$Thus,the correct element is $Pd$.

The element with the electronic configuration $[Kr] \ 4d^{10} \ 5s^0$ is

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