The elevation in boiling point of a solution | vedclass

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(A) Given: Weight of solute $= 10 \ g$,Weight of solvent $= 100 \ g$,Molecular mass of solute $= 100 \ g/mol$.Since it is a binary electrolyte,the van

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$\frac{\Delta T_b}{2}$

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(A) Given: Weight of solute $= 10 \ g$,Weight of solvent $= 100 \ g$,Molecular mass of solute $= 100 \ g/mol$.Since it is a binary electrolyte,the van't Hoff factor $i = 2$.The formula for elevation in boiling point is $\Delta T_b = i 	imes K_b 	imes m$,where $m$ is the molality.$m = \frac{	ext{weight of solute}}{	ext{molecular mass}} 	imes \frac{1000}{	ext{weight of solvent in g}} = \frac{10}{100} 	imes \frac{1000}{100} = 1 \ m$.Substituting the values: $\Delta T_b = 2 	imes K_b 	imes 1$.Therefore,$K_b = \frac{\Delta T_b}{2}$.

The elevation in boiling point of a solution of $10 \ g$ of a binary electrolyte (of molecular mass $100$) in $100 \ g$ of water is $\Delta T_b$. Then,the value of $K_b$ for water is

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