The end product in the reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction sequence is as follows: $1$. The first step is the Reimer-Tiemann reaction,where phenol reacts with $CHCl_3$ and $OH^-$ to form $o$-h

Vedclass · Accepted Answer

Vedclass · Answer

(B) The reaction sequence is as follows: $1$. The first step is the Reimer-Tiemann reaction,where phenol reacts with $CHCl_3$ and $OH^-$ to form $o$-hydroxybenzaldehyde (salicylaldehyde) as the intermediate product $X$. $2$. The second step involves the treatment of $o$-hydroxybenzaldehyde with $50\% \ NaOH$ (concentrated alkali),which leads to the Cannizzaro reaction. $3$. In the Cannizzaro reaction,the aldehyde group is disproportionated into an alcohol group $(-CH_2OH)$ and a carboxylate group $(-COO^-)$. $4$. Thus,the final products $Y$ and $Z$ are $2$-hydroxybenzyl alcohol and $2$-hydroxybenzoate ion,respectively.

Similar Questions

Which of the following compounds is responsible for the iodoform reaction?

$CH_3-CO-CH_3$ $\xrightarrow{NaCN/HCl} A$ $\xrightarrow{H_3O^{+}/\Delta} B$. In the above sequence of reactions,$A$ and $B$ are:

Identify $A$ in the following reaction:

$CH_3-COOH \xrightarrow[(2)\Delta ]{(1)Ca(OH)_2} P$. Compound $P$ can show:

Benzene on reaction with acetyl chloride in the presence of anhydrous $AlCl_3$ gave the product $P$. The product $P$ on reaction with methyl magnesium bromide followed by treatment with water furnished the product $Q$. The molecular formula of $Q$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module