The energies $E_1$ and $E_2$ of two radiations are $25 \ eV$ and $50 \ eV$ respectively. The relation between their wavelengths,i.e.,$\lambda_1$ and $\lambda_2$,will be:
- A$\lambda_1 = \lambda_2$
- B$\lambda_1 = 2 \lambda_2$
- C$\lambda_1 = 4 \lambda_2$
- D$\lambda_1 = \frac{1}{2} \lambda_2$
Explore More
Similar Questions
Find the energy of radiation having $7000 \ \mathring{A}$ and $400 \ nm$ wavelength. $\left( h = 6.62 \times 10^{-34} \ J \ s, c = 3 \times 10^8 \ m/s \right)$
Easy
View SolutionThe wavelength of $X$-ray is $1.5 \times 10^{-10} \ m$. Find the frequency.
Easy
View SolutionArrange the following types of radiation in increasing order of frequency:
$(a)$ radiation from microwave oven
$(b)$ amber light from traffic signal
$(c)$ radiation from $FM$ radio
$(d)$ cosmic rays from outer space
$(e)$ $X$-rays
$(a)$ radiation from microwave oven
$(b)$ amber light from traffic signal
$(c)$ radiation from $FM$ radio
$(d)$ cosmic rays from outer space
$(e)$ $X$-rays
Medium
View SolutionExplain emission and absorption spectra.
Difficult
View SolutionThe following sketch represents a specific wave of light. What will be the color of the light represented by this wave?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo