The energy (in eV) required to excite an elec | vedclass

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(A) In a hydrogen atom,the energy of an electron in a state $n$ is given by the formula $E_n = -\frac{13.6}{n^2} 	ext{ eV}$.To excite an electron fro

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+ $2.55$

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(A) In a hydrogen atom,the energy of an electron in a state $n$ is given by the formula $E_n = -\frac{13.6}{n^2} 	ext{ eV}$.To excite an electron from state $n_i = 2$ to state $n_f = 4$,the energy required is $\Delta E = E_4 - E_2$.First,calculate the energy of the $n=2$ state: $E_2 = -\frac{13.6}{2^2} = -\frac{13.6}{4} = -3.4 	ext{ eV}$.Next,calculate the energy of the $n=4$ state: $E_4 = -\frac{13.6}{4^2} = -\frac{13.6}{16} = -0.85 	ext{ eV}$.The energy required is $\Delta E = -0.85 - (-3.4) = 3.4 - 0.85 = 2.55 	ext{ eV}$.

The energy (in $eV$) required to excite an electron from $n=2$ to $n=4$ state in a hydrogen atom is:

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