The energy liberated on complete fission of $1\, kg$ of $_{92}{U^{235}}$ is (Assume $200\, MeV$ energy is liberated on fission of $1$ nucleus).

In a hypothetical fission reaction
${ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R$
The identity of emitted particles $(R)$ is :

Imagine that a reactor converts all given mass into energy and that it operates at a power level of $10^9\, W$. The mass of the fuel consumed per hour in the reactor will be: (velocity of light,$c = 3 \times 10^8\, m/s$)

Light energy emitted by stars is due to

When a $_4Be^9$ atom is bombarded with $\alpha$-particles,one of the products of nuclear transmutation is $_6C^{12}$. The other product is:

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:
${ }_{1}^{2} X +{ }_{1}^{2} X ={ }_{2}^{4} Y$
The binding energies per nucleon of ${ }_{1}^{2} X$ and ${ }_{2}^{4} Y$ are $1.1 \, MeV$ and $7.6 \, MeV$ respectively. The energy released in this process is in $MeV$.