The energy of a mole of light quanta is 72 k | vedclass

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(B) The photosynthetic equation is $6CO_2 + 12H_2O + 	ext{Light Energy} ightarrow C_6H_{12}O_6 + 6O_2 + 6H_2O$. To synthesize $1 \ mole$ of glucose

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$1968 \ to \ 3456 \ kcal$

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(B) The photosynthetic equation is $6CO_2 + 12H_2O + 	ext{Light Energy} ightarrow C_6H_{12}O_6 + 6O_2 + 6H_2O$. To synthesize $1 \ mole$ of glucose,$686 \ kcal$ of energy is stored in the chemical bonds. Photosynthesis is not $100\%$ efficient. According to the quantum requirement,$8 \ quanta$ are required to evolve $1 \ mole$ of $O_2$. For $1 \ mole$ of glucose,$6 \ moles$ of $O_2$ are evolved,thus requiring $6 	imes 8 = 48 \ quanta$ (moles of photons). In the blue region $(400 \ nm)$,$1 \ mole$ of quanta provides $72 \ kcal$. Total energy required = $48 	imes 72 = 3456 \ kcal$. In the red region $(700 \ nm)$,$1 \ mole$ of quanta provides $41 \ kcal$. Total energy required = $48 	imes 41 = 1968 \ kcal$. Thus,the range of energy required is $1968 \ to \ 3456 \ kcal$.

The energy of a mole of light quanta is $72 \ kcal$ in the blue region at $400 \ nm$ and $41 \ kcal$ in the red region at $700 \ nm$. How much light energy would be required under standard conditions to make $1 \ mole$ of glucose costing $686 \ kcal$?

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