The energy of an electron revolving in the $n^{th}$ Bohr's orbit of an atom is given by the expression

  • A
    $E_n = - \frac{2\pi^2 m^4 e^2 z^2}{n^2 h^2}$
  • B
    $E_n = - \frac{2\pi^2 m e^2 z^2}{n^2 h^2}$
  • C
    $E_n = - \frac{2\pi^2 m e^4 z^2}{n^2 h^2}$
  • D
    $E_n = - \frac{2\pi m^2 e^2 z^4}{n^2 h^2}$

Explore More

Similar Questions

Circumference of the first orbit of hydrogen atom is given by the formula :

Maximum frequency of emission is obtained for the transition $:-$

What is the kinetic energy of an electron in the second excited state of $He^{+}$? (Energy of an electron in the first shell of $H = -13.6 \ eV$)

In the atomic spectrum of hydrogen, the wavelengths of the spectral lines corresponding to electronic transitions $(i)$ $n=4$ to $n=2$ and $(ii)$ $n=3$ to $n=1$ are $\lambda_1$ and $\lambda_2$ $\mathring{A}$ respectively. The value of $(\lambda_1-\lambda_2)$ (in cm) is ($R_H$ = Rydberg constant)

Energy levels $A, B, C$ of a certain atom correspond to increasing values of energy,$i.e.,$ $E_A < E_B < E_C$. If $\lambda_1, \lambda_2$ and $\lambda_3$ are the wavelengths of radiations corresponding to the transitions $C$ to $B$,$B$ to $A$ and $C$ to $A$ respectively,which of the following statements is correct?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo