The energy of the electron at infinite distan | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the Bohr model,the energy of an electron in the $n^{th}$ orbit is given by the expression $E_{n} = -13.6 	imes \frac{Z^{2}}{n^{2}} 	ext{ eV}$

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(A) In the Bohr model,the energy of an electron in the $n^{th}$ orbit is given by the expression $E_{n} = -13.6 	imes \frac{Z^{2}}{n^{2}} 	ext{ eV}$.As the distance from the nucleus increases,the value of $n$ increases.When the electron is at an infinite distance from the nucleus,$n = \infty$.Substituting $n = \infty$ into the formula,we get $E_{\infty} = -13.6 	imes \frac{Z^{2}}{\infty^{2}} = 0$.Therefore,the energy of the electron at infinite distance from the nucleus is taken as zero.

The energy of the electron at infinite distance from the nucleus in Bohr’s model is taken as:

Similar Questions

Which of the following statements regarding the $H$ atom spectrum is correct?

$A$ bulb emits light of wavelength $4500 \ \mathring{A}$. The bulb is rated at $150 \ \text{W}$ and $8\%$ of the energy is emitted as light. How many photons are emitted by the bulb per second?

Based on equation $E = -2.178 \times 10^{-18} \ J \ \frac{Z^2}{n^2}$,certain conclusions are written. Which of them is not correct?

Find the wave number of the shortest wavelength in the Balmer series.

In a $He^{+}$ ion,an electronic transition occurs from orbit $n_2$ to $n_1$ such that:
$2n_2 + 3n_1 = 18$
$2n_2 - 3n_1 = 6$
What is the total number of photons emitted when the electron transitions to the $n_1$ orbit?

Vedclass Test Series

Exam Paper Generator

Online Exam Module