The energy required to remove the electron fr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy required to remove an electron from a singly ionized Helium atom $(He^+)$ is given by the formula $E = 13.6 	imes Z^2 / n^2$ eV.For $H

Vedclass · Accepted Answer

$79$

Vedclass · Answer

(B) The energy required to remove an electron from a singly ionized Helium atom $(He^+)$ is given by the formula $E = 13.6 	imes Z^2 / n^2$ eV.For $He^+$,$Z = 2$ and $n = 1$,so $E_1 = 13.6 	imes 2^2 / 1^2 = 54.4$ eV.Let the energy required to remove the first electron from a neutral Helium atom be $x$ eV.According to the problem,$54.4 = 2.2 	imes x$.Solving for $x$,we get $x = 54.4 / 2.2 \approx 24.73$ eV.The total energy required to ionize the Helium atom completely is the sum of the energy to remove the first electron and the energy to remove the second electron from the resulting $He^+$ ion.Total Energy $= x + 54.4 = 24.73 + 54.4 = 79.13$ eV.Rounding to the nearest integer,we get $79$ eV.

The energy required to remove the electron from a singly ionized Helium atom is $2.2$ times the energy required to remove an electron from a Helium atom. The total energy required to ionize the Helium atom completely is......$eV$

Similar Questions

What is the moment of inertia of the electron moving in the second Bohr orbit of a hydrogen atom? ($h=$ Planck's constant,$m=$ mass of electron,$\varepsilon_0=$ permittivity of free space,$e=$ charge on electron)

What is ground state?

If the radius of the first Bohr orbit is $r$, then the radius of the second Bohr orbit will be

The ground state energy of a hydrogen atom is $-13.6 \text{ eV}$. The potential and kinetic energies of the electron in this state are . . . . . . .

The ionisation energy of $10$ times ionised sodium atom is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module