The energy stored in a capacitor is $W$. To double the charge on the plates of the capacitor,the additional work to be done is

$A$ parallel plate capacitor having plate area $A$ and separation $d$ is charged to a potential difference $V$. The charging battery is disconnected and the plates are pulled apart to four times the initial separation. The work required to increase the distance between the plates is ($\epsilon_0 =$ permittivity of free space).

Energy is stored in what form in a capacitor?

The charge $q$ on a capacitor varies with voltage $V$ as shown in the graph. The area of $\Delta OPM$ represents:

$A$ capacitor of capacitance $10 \mu F$ is charged to $10 \text{ V}$. The energy stored in it is (in $\mu J$)

If the potential of a capacitor having capacity of $6\,\mu F$ is increased from $10\,V$ to $20\,V$,then the increase in its energy will be: