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(B) The daily collection is calculated as: $	ext{Daily Collection} = 	ext{Price of one ticket} 	imes 	ext{Number of visitors}$.The ratio of the pr

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$247500$

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(B) The daily collection is calculated as: $	ext{Daily Collection} = 	ext{Price of one ticket} 	imes 	ext{Number of visitors}$.The ratio of the price change is $7:9$ and the ratio of the change in the number of visitors is $13:11$.Therefore,the ratio of the daily collection before and after the change is $(7 	imes 13) : (9 	imes 11) = 91 : 99$.Given that the daily collection before the price hike was $₹ 2,27,500$,we can set up the equation:$\frac{	ext{Old Collection}}{	ext{New Collection}} = \frac{91}{99}$.New daily collection $= 2,27,500 	imes \left(\frac{99}{91}ight)$.First,divide $2,27,500$ by $91$: $2,27,500 / 91 = 2,500$.Then,multiply by $99$: $2,500 	imes 99 = 2,47,500$.Thus,the new daily collection is $₹ 2,47,500$.

The entry ticket price at a fun park was increased in the ratio $7:9$,due to which the number of visitors (footfalls) decreased in the ratio $13:11$. If the daily collection before the price hike was $₹ 2,27,500$,what is the new daily collection (in $₹$)?

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