The equation of a transverse wave is given by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The standard equation of a transverse wave is given by $y = A \sin(kz - \omega t)$.Comparing the given equation $y = 100 \sin \pi (0.04z - 2t)$ wi

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The standard equation of a transverse wave is given by $y = A \sin(kz - \omega t)$.Comparing the given equation $y = 100 \sin \pi (0.04z - 2t)$ with the standard form,we distribute $\pi$ inside the parentheses:$y = 100 \sin (0.04\pi z - 2\pi t)$.Here,the angular frequency $\omega$ is the coefficient of $t$,which is $\omega = 2\pi 	ext{ rad/s}$.The relationship between angular frequency $\omega$ and frequency $f$ is $\omega = 2\pi f$.Substituting the value of $\omega$:$2\pi = 2\pi f$.Therefore,$f = 1 	ext{ Hz}$.

The equation of a transverse wave is given by $y = 100 \sin \pi (0.04z - 2t)$,where $y$ and $z$ are in $cm$ and $t$ is in seconds. The frequency of the wave in $Hz$ is

Similar Questions

The equation of a wave motion (with $t$ in seconds and $x$ in metres) is given by $y = 7\sin(7\pi t - 0.4\pi x + \frac{\pi}{3})$. The velocity of the wave will be

$A$ progressive sound wave is represented by $y = a \sin(400\pi t - \pi x / 6.85)$,where $x$ is in $m$ and $t$ is in $s$. The frequency of the wave is .... $Hz$.

The transverse displacement $y(x, t)$ of a wave on a string is given by $y(x, t) = e^{-(ax^2 + bt^2 + 2\sqrt{ab}xt)}$. This represents a

Write the definition of the angular frequency of a wave and its $SI$ unit.

$A$ transverse wave is described by the equation $Y = Y_0 \sin 2\pi \left( ft - \frac{x}{\lambda} \right)$. The maximum particle velocity is four times the wave velocity if:

Vedclass Test Series

Exam Paper Generator

Online Exam Module