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(B) The standard equation of a travelling wave is given by $y = a \sin(kx - \omega t)$.Comparing the given equation $y = 0.5 \sin(20x - 400t)$ with th

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$20$

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(B) The standard equation of a travelling wave is given by $y = a \sin(kx - \omega t)$.Comparing the given equation $y = 0.5 \sin(20x - 400t)$ with the standard form,we identify the wave number $k = 20 	ext{ rad/m}$ and the angular frequency $\omega = 400 	ext{ rad/s}$.The velocity of the wave $v$ is given by the ratio of angular frequency to wave number:$v = \frac{\omega}{k}$Substituting the values:$v = \frac{400}{20} = 20 	ext{ m/s}$.Thus,the velocity of the wave is $20 	ext{ m/s}$.

The equation of a travelling wave is given by $y = 0.5 \sin(20x - 400t)$,where $x$ and $y$ are in meters and $t$ is in seconds. The velocity of the wave is .... $m/s$.

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