Class 11MathematicsPair of straight linesBisectors of the angle between the lines, Point of intersection of the lines
EasyThe equation of the bisectors of the angle between the lines given by $3x^2+5xy+4y^2=0$ is
- A$x^2-y^2-\frac{2}{5}xy=0$
- B$x^2-y^2+\frac{2}{5}xy=0$
- C$x^2-y^2-\frac{1}{5}xy=0$
- D$x^2-y^2+\frac{1}{5}xy=0$
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Similar Questions
The equation of the bisectors of the angle between the lines represented by the equation ${x^2} - {y^2} = 0$ is:
Medium
View SolutionIf the bisectors of the angles between the pairs of lines given by the equations $ax^2 + 2hxy + by^2 = 0$ and $ax^2 + 2hxy + by^2 + \lambda(x^2 + y^2) = 0$ are coincident,then $\lambda = $
Medium
View SolutionSuppose the pairs of straight lines $x^2 - 2axy - y^2 = 0$ and $x^2 - 2bxy - y^2 = 0$ are such that each pair bisects the angles between the other. Then $ab =$
The line $x - 2y = 0$ will be a bisector of the angle between the lines represented by the equation ${x^2} - 2hxy - 2{y^2} = 0$,if $h = $
Medium
View SolutionThe area of the triangle formed by the line $x+y=4$ and the angle bisectors of the pair of lines $x^2-y^2+2y-1=0$ is ......... sq. units.
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