The equation of the circle whose diameters have the end points $(a, 0)$ and $(0, b)$ is given by:
- A$x^2 + y^2 - ax - by = 0$
- B$x^2 + y^2 + ax - by = 0$
- C$x^2 + y^2 - ax + by = 0$
- D$x^2 + y^2 + ax + by = 0$
Explore More
Similar Questions
Two points from the set of concyclic points of the circle passing through $(1,1), (2,-1),$ and $(3,2)$ are:
DifficultTS EAMCET 2020
View Solution$A$ circle passing through $(0,0)$, $(2,6)$, and $(6,2)$ cuts the $x$-axis at the point $P \neq (0,0)$. Then, the length of $OP$, where $O$ is the origin, is
MediumWBJEE 2013
View SolutionFind the equation of the circle which passes through the points $(2, -2)$ and $(3, 4)$ and whose centre lies on the line $x + y = 2$.
Medium
View SolutionFind the centre and radius of the circle $x^{2}+y^{2}-4x-8y-45=0$.
Easy
View SolutionThe circle represented by the equation $x^2 + y^2 + 2gx + 2fy + c = 0$ will be a point circle,if
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo