The equation of the line passing through (a, | vedclass

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(B) The given line is $\frac{x}{a} + \frac{y}{b} = 1$,which can be written as $y = -\frac{b}{a}x + b$. The slope of this line is $m = -\frac{b}{a}$. S

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$\frac{x}{a} + \frac{y}{b} = 2$

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(B) The given line is $\frac{x}{a} + \frac{y}{b} = 1$,which can be written as $y = -\frac{b}{a}x + b$. The slope of this line is $m = -\frac{b}{a}$. Since the required line is parallel to this line,its slope will also be $m = -\frac{b}{a}$. The equation of the line passing through $(a, b)$ with slope $m = -\frac{b}{a}$ is given by $y - b = m(x - a)$. Substituting the values: $y - b = -\frac{b}{a}(x - a)$. Dividing both sides by $b$: $\frac{y}{b} - 1 = -\frac{1}{a}(x - a)$. $\frac{y}{b} - 1 = -\frac{x}{a} + 1$. Rearranging the terms: $\frac{x}{a} + \frac{y}{b} = 2$.

The equation of the line passing through $(a, b)$ and parallel to the line $\frac{x}{a} + \frac{y}{b} = 1$ is

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