(D) Given equations are $y - x + 7 = 0$ $(1)$ and $y + 2x - 2 = 0$ $(2)$.Subtracting $(1)$ from $(2)$,we get $(y + 2x - 2) - (y - x + 7) = 0$,which si

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Given equations are $y - x + 7 = 0$ $(1)$ and $y + 2x - 2 = 0$ $(2)$.Subtracting $(1)$ from $(2)$,we get $(y + 2x - 2) - (y - x + 7) = 0$,which simplifies to $3x - 9 = 0$,so $x = 3$.Substituting $x = 3$ in $(1)$,we get $y - 3 + 7 = 0$,so $y = -4$.The point of intersection is $(3, -4)$.The equation of a line passing through the origin $(0, 0)$ and $(x_1, y_1)$ is given by $y = \frac{y_1}{x_1}x$.Substituting $(3, -4)$,we get $y = \frac{-4}{3}x$,which implies $3y = -4x$ or $4x + 3y = 0$.

Class 11 Mathematics Pair of straight lines Equation of lines joining the origin to the point of intersection of a curve and a line and Distance between the pair of lines

Easy

The equation of the straight line joining the origin to the point of intersection of $y - x + 7 = 0$ and $y + 2x - 2 = 0$ is

A
$3x + 4y = 0$
B
$3x - 4y = 0$
C
$4x - 3y = 0$
D
$4x + 3y = 0$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Mathematics Questions

Chapter

Pair of straight lines

Subtopic

Equation of lines joining the origin to the point of intersection of a curve and a line and Distance between the pair of lines

$A$ pair of perpendicular lines passes through the origin and also through the points of intersection of the curve $x^2+y^2=4$ with $x+y=a$,where $a>0$. Then $a$ is equal to

DifficultAP EAMCET 2010

View Solution

The equation $8x^2 + 8xy + 2y^2 + 26x + 13y + 15 = 0$ represents a pair of parallel straight lines. The distance between them is

Medium

View Solution

The lines joining the points of intersection of the line $x + y = 1$ and the curve $x^2 + y^2 - 2y + \lambda = 0$ to the origin are perpendicular. Then the value of $\lambda$ is:

Difficult

View Solution

The area (in sq. units) of the triangle formed by the lines $x^2-3xy+y^2=0$ and $x+y+1=0$ is

DifficultTS EAMCET 2014

View Solution

The distance between the pair of parallel lines $x^2 + 2xy + y^2 - 8ax - 8ay - 9a^2 = 0$ is

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The equation of the straight line joining the origin to the point of intersection of $y - x + 7 = 0$ and $y + 2x - 2 = 0$ is

Similar Questions

$A$ pair of perpendicular lines passes through the origin and also through the points of intersection of the curve $x^2+y^2=4$ with $x+y=a$,where $a>0$. Then $a$ is equal to

The equation $8x^2 + 8xy + 2y^2 + 26x + 13y + 15 = 0$ represents a pair of parallel straight lines. The distance between them is

The lines joining the points of intersection of the line $x + y = 1$ and the curve $x^2 + y^2 - 2y + \lambda = 0$ to the origin are perpendicular. Then the value of $\lambda$ is:

The area (in sq. units) of the triangle formed by the lines $x^2-3xy+y^2=0$ and $x+y+1=0$ is

The distance between the pair of parallel lines $x^2 + 2xy + y^2 - 8ax - 8ay - 9a^2 = 0$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module