The equilibrium constants for the following r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given reactions:$(i) 2 A \rightleftharpoons B + C, K_{1} = 1$$(ii) 2 B \rightleftharpoons C + D, K_{2} = 16$$(iii) 2 C + D \rightleftharpoons 2 P,

Vedclass · Accepted Answer

$\frac{1}{20}$

Vedclass · Answer

(A) Given reactions:$(i) 2 A ightleftharpoons B + C, K_{1} = 1$$(ii) 2 B ightleftharpoons C + D, K_{2} = 16$$(iii) 2 C + D ightleftharpoons 2 P, K_{3} = 25$We need the equilibrium constant for $P ightleftharpoons A + \frac{1}{2} B$.Reverse reaction $(iii)$ and divide by $2$: $P ightleftharpoons C + \frac{1}{2} D, K' = \sqrt{\frac{1}{K_{3}}} = \frac{1}{5}$.Reverse reaction $(ii)$ and divide by $2$: $\frac{1}{2} C + \frac{1}{2} D ightleftharpoons B, K'' = \sqrt{\frac{1}{K_{2}}} = \frac{1}{4}$.Reverse reaction $(i)$ and divide by $2$: $\frac{1}{2} B + \frac{1}{2} C ightleftharpoons A, K''' = \sqrt{\frac{1}{K_{1}}} = 1$.Adding these reactions: $P + \frac{1}{2} C + \frac{1}{2} D + \frac{1}{2} B + \frac{1}{2} C ightleftharpoons C + \frac{1}{2} D + B + A$.Simplifying: $P ightleftharpoons A + \frac{1}{2} B$.The equilibrium constant $K_{final} = K' 	imes K'' 	imes K''' = \frac{1}{5} 	imes \frac{1}{4} 	imes 1 = \frac{1}{20}$.

Similar Questions

Write the uses of equilibrium constant.

For the reaction $CH_3COOH + H_2O \rightleftharpoons H_3O^{+} + CH_3COO^{-}$,the equilibrium constant $K$ is given by:

At $400 \ K$ for the reaction $2NO_{2(g)} \rightleftharpoons N_{2}O_{4(g)}$,the concentration of $NO_{2}$ is $0.710 \ M$ and $N_{2}O_{4}$ is $0.145 \ M$. Find the equilibrium constant $K_{c}$. (in $M^{-1}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module