The equilibrium which remains unaffected by a | vedclass

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Question

(A) According to Le Chatelier's principle,a change in pressure affects the equilibrium position only if there is a change in the total number of moles

Vedclass · Accepted Answer

$N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$

Vedclass · Answer

(A) According to Le Chatelier's principle,a change in pressure affects the equilibrium position only if there is a change in the total number of moles of gaseous species between reactants and products (i.e.,$\Delta n_g 
eq 0$).If $\Delta n_g = 0$,the equilibrium remains unaffected by a change in pressure.For option $A$: $\Delta n_g = 2 - (1 + 1) = 0$.For option $B$: $\Delta n_g = 2 - (2 + 1) = -1$.For option $C$: $\Delta n_g = 3 - 2 = 1$.For option $D$: $\Delta n_g = 1 - 2 = -1$.Since $\Delta n_g = 0$ for reaction $A$,it is unaffected by pressure changes.

The equilibrium which remains unaffected by a change in pressure is:

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