The equivalent capacitance between points $A$ and $B$ of the circuit shown will be

  • A
    $\frac{2}{3} \, \mu F$
  • B
    $\frac{5}{3} \, \mu F$
  • C
    $\frac{8}{3} \, \mu F$
  • D
    $\frac{7}{3} \, \mu F$

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