The equivalent capacitance of the combination shown in the figure is:

The equivalent capacitance between $A$ and $B$ is......$\mu F$.

Two capacitors of capacitance $2 \mu F$ and $4 \mu F$ respectively are connected in series. The combination is connected across a potential difference of $10 \ V$. The ratio of energies stored by the capacitors will be . . . . . . .

Two capacitors of capacities $2 \mu F$ and $4 \mu F$ are connected in parallel. $A$ third capacitor of $6 \mu F$ capacity is connected in series with this combination. $A$ battery of $12 \text{ V}$ is connected across this combination. The charge on the $2 \mu F$ capacitor is: (in $\mu C$)

Three capacitors of $2\,\mu F$,$3\,\mu F$,and $6\,\mu F$ are joined in series,and the combination is charged by means of a $24\,V$ battery. The potential difference across the plates of the $6\,\mu F$ capacitor is.......$V$.

In the circuit shown in the figure,the potential difference across the $4.5\,\mu F$ capacitor is.......$V$.