The equivalent capacitance of the combination | vedclass

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(D) In the given circuit, the two capacitors on the left are connected in series. Let their equivalent capacitance be $C_s$. $C_s = \frac{C 	imes C}{

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$\frac{3}{2} C$

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(D) In the given circuit, the two capacitors on the left are connected in series. Let their equivalent capacitance be $C_s$. $C_s = \frac{C 	imes C}{C + C} = \frac{C^2}{2C} = \frac{C}{2}$. Now, this equivalent capacitor $C_s$ is in parallel with the third capacitor $C$ connected between the middle junction and point $N$. Therefore, the total equivalent capacitance $C_{eq}$ between points $P$ and $N$ is: $C_{eq} = C_s + C = \frac{C}{2} + C = \frac{3C}{2}$.

The equivalent capacitance of the combination of capacitors shown in the figure between the points $P$ and $N$ is:

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