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(A) From the circuit diagram,we can see that point $A$ is connected to point $D$ by a wire,so $V_A = V_D$.Similarly,point $C$ is connected to point $B

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$5$

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(A) From the circuit diagram,we can see that point $A$ is connected to point $D$ by a wire,so $V_A = V_D$.Similarly,point $C$ is connected to point $B$ by a wire,so $V_C = V_B$.There are three resistors connected between these two common potential points $(A, D)$ and $(B, C)$:$1$. $A$ $10\,k\Omega$ resistor between $D$ and $B$.$2$. $A$ $20\,k\Omega$ resistor between $A$ and $C$.$3$. $A$ $20\,k\Omega$ resistor between $C$ and $D$.Since all three resistors are connected in parallel,the equivalent resistance $R_{eq}$ is given by:$\frac{1}{R_{eq}} = \frac{1}{10} + \frac{1}{20} + \frac{1}{20}$$\frac{1}{R_{eq}} = \frac{2 + 1 + 1}{20} = \frac{4}{20} = \frac{1}{5}$Therefore,$R_{eq} = 5\,k\Omega$.

The equivalent resistance between $A$ and $B$ as shown in the figure is $........\,k\Omega$.

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