The equivalent resistance between P and Q in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given circuit is a balanced Wheatstone bridge.In a Wheatstone bridge,if the ratio of resistances in opposite arms is equal,the central resisto

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(D) The given circuit is a balanced Wheatstone bridge.In a Wheatstone bridge,if the ratio of resistances in opposite arms is equal,the central resistor carries no current.Here,all four outer resistors are $20 \ \Omega$,so the ratio is $20/20 = 20/20 = 1$.Since the bridge is balanced,the central $20 \ \Omega$ resistor can be removed.Now,the circuit consists of two parallel branches,each having two $20 \ \Omega$ resistors in series.Resistance of the upper branch = $20 \ \Omega + 20 \ \Omega = 40 \ \Omega$.Resistance of the lower branch = $20 \ \Omega + 20 \ \Omega = 40 \ \Omega$.These two branches are in parallel,so the equivalent resistance $R_{eq}$ is given by:$1/R_{eq} = 1/40 + 1/40 = 2/40 = 1/20$.Therefore,$R_{eq} = 20 \ \Omega$.

The equivalent resistance between $P$ and $Q$ in the given figure is ............... $\Omega$.

Similar Questions

What is the equivalent resistance between $A$ and $D$ in the given circuit? (All resistors are $10 \,\Omega$)

Five current-carrying conductors meet at a point $P$. Based on the provided image,what is the magnitude and direction of the current in the fifth conductor connected to point $Q$?

The potential difference between points $C$ and $D$ of the electrical circuit shown in the figure is (in $V$)

The value of current in the $6 \,\Omega$ resistance is $....\,A$

If the charge on the capacitor is $1 \text{ mC}$ in the given circuit,then $\frac{R_1 R_2}{R_3} = \ldots \ldots \ldots \Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module