The equivalent resistance of the circuit show | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The circuit consists of three parts connected in series: a $2\,\Omega$ resistor,a parallel combination of two $2\,\Omega$ resistors,and another $2

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) The circuit consists of three parts connected in series: a $2\,\Omega$ resistor,a parallel combination of two $2\,\Omega$ resistors,and another $2\,\Omega$ resistor.First,calculate the equivalent resistance of the two $2\,\Omega$ resistors in parallel:$\frac{1}{R_p} = \frac{1}{2} + \frac{1}{2} = 1 \implies R_p = 1\,\Omega$.Now,the total equivalent resistance $R_{eq}$ is the sum of the series components:$R_{eq} = 2\,\Omega + R_p + 2\,\Omega = 2\,\Omega + 1\,\Omega + 2\,\Omega = 5\,\Omega$.

The equivalent resistance of the circuit shown in the figure is ............. $\Omega$

Similar Questions

An electric heater and an electric bulb are rated $500\, W, 220\, V$ and $100\, W, 220\, V$ respectively. Both are connected in series to a $220\, V$ $a.c.$ mains. The current in the circuit when both are connected in series is ................ $A$.

Twelve wires of equal length and same cross-section are connected in the form of a cube. If the resistance of each of the wires is $R$,then the effective resistance between the two diagonal ends would be

$A$ wire of resistance $12 \, \Omega/m$ is bent to form a complete circle of radius $10 \, cm$. The resistance between its two diametrically opposite points, $A$ and $B$, as shown in the figure, is:

The equivalent resistance between $A$ and $B$ is

Find the equivalent resistance between $P$ and $Q$. (If each wire has a resistance $R$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module