The escape velocity of a body from a planet of mass $M$ and radius $R$ is $14 \,km \,s^{-1}$. The escape velocity of the body from another planet having same mass and diameter $8R$ (in $km \,s^{-1}$) is

If the radius and acceleration due to gravity both are doubled,the escape velocity of the Earth will become ......... $km/s$.

Given the mass of the moon is $1/81$ of the mass of the earth and its radius is $1/4$ of the earth's radius. If the escape velocity on the earth's surface is $11.2 \, km/s$,the value of the escape velocity on the surface of the moon is ......... $km/s$.

The radius of the planet is double that of the earth,but their average densities are same. $V_{p}$ and $V_E$ are the escape velocities of planet and earth respectively. If $\frac{V_p}{V_E}=x$,the value of '$x$' is

On which two factors does the escape velocity of an object projected from the Earth $NOT$ depend?

Escape velocity on Earth is $11.2 \, km/s$. What would be the escape velocity on a planet whose mass is $1000$ times and radius is $10$ times that of Earth?