The exact order of boiling points of the comp | vedclass

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Question

(B) The boiling point depends on the strength of intermolecular forces. The order of strength of intermolecular forces is: $	ext{Hydrogen bonding} >

Vedclass · Accepted Answer

isopentane < $n$-pentane < butanone < $1$-butanol

Vedclass · Answer

(B) The boiling point depends on the strength of intermolecular forces. The order of strength of intermolecular forces is: $ ext{Hydrogen bonding} > ext{Dipole-dipole interaction} > ext{Van der Waals forces}$.$1$. $1$-butanol $(CH_3CH_2CH_2CH_2OH)$ exhibits intermolecular hydrogen bonding, which is the strongest force among the given compounds, resulting in the highest boiling point.$2$. Butanone $(CH_3COCH_2CH_3)$ is a polar molecule and exhibits dipole-dipole interactions, which are stronger than Van der Waals forces but weaker than hydrogen bonding.$3$. $n$-pentane and isopentane are non-polar alkanes and exhibit only Van der Waals forces. For alkanes, the boiling point decreases with branching because branching reduces the surface area of contact, leading to weaker Van der Waals forces. Thus, $n$-pentane has a higher boiling point than isopentane.Therefore, the correct order of boiling points is: $ ext{isopentane} < n ext{-pentane} < ext{butanone} < 1 ext{-butanol}$.

The exact order of boiling points of the compounds $n$-pentane, isopentane, butanone, and $1$-butanol is:

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