The expression for Y in the following circuit | vedclass

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(C) $1$. The first gate is a $NOR$ gate with inputs $A$ and $1$. The output of this $NOR$ gate is $\overline{A+1}$. Since $A+1 = 1$,the output is $\ov

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$B+C$

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(C) $1$. The first gate is a $NOR$ gate with inputs $A$ and $1$. The output of this $NOR$ gate is $\overline{A+1}$. Since $A+1 = 1$,the output is $\overline{1} = 0$.$2$. The second gate is an $OR$ gate with inputs from the first gate (which is $0$) and input $B$. The output of this $OR$ gate is $0+B = B$.$3$. The third gate is an $OR$ gate with inputs from the second gate (which is $B$) and input $C$. The output $Y$ is $B+C$.

The expression for $Y$ in the following circuit is

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