The figure represents the momentum-time (p-t) | vedclass

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(C) According to Newton's second law of motion,the force $\vec{F}$ acting on a particle is equal to the rate of change of momentum with respect to tim

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$c$ and $b$

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(C) According to Newton's second law of motion,the force $\vec{F}$ acting on a particle is equal to the rate of change of momentum with respect to time: $\vec{F} = \frac{d\vec{p}}{dt}$.This implies that the magnitude of the force $|\vec{F}|$ is equal to the magnitude of the slope of the $p-t$ graph: $|\vec{F}| = |	ext{slope of } p-t 	ext{ curve}|$.$1$. In region $a$,the slope is positive and moderate.$2$. In region $b$,the slope is positive and small (the line is nearly horizontal).$3$. In region $c$,the slope is negative and its magnitude is very large (the line is very steep).Comparing the magnitudes of the slopes,the slope is maximum in region $c$ and minimum in region $b$.Therefore,the magnitude of the force is maximum in region $c$ and minimum in region $b$.

The figure represents the momentum-time $(p-t)$ curve for a particle moving along an axis under the influence of a force. Identify the regions on the graph where the magnitude of the force is maximum and minimum,respectively.

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