The figure shows a network of resistors and a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the potential at node $F$ be $0\,V$. Since $F, G, H$ are connected by wires,$V_F = V_G = V_H = 0\,V$.Given current through branch $CF$ is $1\,

Vedclass · Accepted Answer

Both $(A)$ and $(B)$

Vedclass · Answer

(D) Let the potential at node $F$ be $0\,V$. Since $F, G, H$ are connected by wires,$V_F = V_G = V_H = 0\,V$.Given current through branch $CF$ is $1\,A$,so $V_C - V_F = I_{CF} 	imes R_{CF} \implies V_C - 0 = 1\,A 	imes 2\,\Omega = 2\,V$.Now,consider the branch $CD-DE-EF$. The resistance of branch $DE$ is $1\,\Omega + 1\,\Omega = 2\,\Omega$ (in series).The current through branch $DE$ is $I_{DE} = \frac{V_C - V_E}{R_{DE}} = \frac{2\,V - 0\,V}{2\,\Omega} = 1\,A$.Now,applying Kirchhoff's Current Law at node $C$,the total current entering $C$ from $B$ is $I_{BC} = I_{CF} + I_{DE} = 1\,A + 1\,A = 2\,A$.Thus,the current through branch $DE$ is $1\,A$ and the current through branch $BC$ is $2\,A$.Therefore,both $(A)$ and $(B)$ are correct.

The figure shows a network of resistors and a battery. If $1\,A$ current flows through the branch $CF$,then find the current through the branches $DE$ and $BC$.

Similar Questions

Six equal resistances $R$ are connected between points $P$,$Q$,and $R$ as shown in the figure. Then the net resistance will be maximum between:

In the given figure,the steady state current $I$ is ................. $A$.

In the given circuit,the potentials at points $B$,$C$,and $D$ will be:

In the circuit shown in the figure below,which of the following statements is incorrect?

What is the equivalent resistance between $A$ and $B$ in the given infinite network?

Vedclass Test Series

Exam Paper Generator

Online Exam Module