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(A) According to Kirchhoff's current law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.At junction $A$,the inc

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$3.5$

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(A) According to Kirchhoff's current law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.At junction $A$,the incoming currents are $1 \ A$ and $4 \ A$. Therefore,the current leaving junction $A$ towards junction $B$ is $I_{AB} = 1 \ A + 4 \ A = 5 \ A$.At junction $B$,the incoming current is $I_{AB} = 5 \ A$. The outgoing currents are $0.5 \ A$ and the current towards junction $C$ $(I_{BC})$. Thus,$5 \ A = 0.5 \ A + I_{BC}$,which gives $I_{BC} = 4.5 \ A$.At junction $C$,the incoming current is $I_{BC} = 4.5 \ A$. The outgoing currents are $I$ and $1 \ A$. Thus,$4.5 \ A = I + 1 \ A$,which gives $I = 3.5 \ A$.

The figure shows currents in a part of an electric circuit. Then the current $I$ is: (in $A$)

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