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(B) For a prism, the angle of deviation $\delta$ is given by the formula: $\delta = i + e - A$, where $i$ is the angle of incidence, $e$ is the angle

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(B) For a prism, the angle of deviation $\delta$ is given by the formula: $\delta = i + e - A$, where $i$ is the angle of incidence, $e$ is the angle of emergence, and $A$ is the prism angle.From the graph, we observe that for a deviation $\delta = 30^{\circ}$, there are two possible angles of incidence: $i_1 = 15^{\circ}$ and $i_2 = 60^{\circ}$.By the principle of reversibility of light, if $i = 15^{\circ}$, then $e = 60^{\circ}$, and if $i = 60^{\circ}$, then $e = 15^{\circ}$.Substituting these values into the formula: $A = i + e - \delta$.$A = 15^{\circ} + 60^{\circ} - 30^{\circ}$.$A = 75^{\circ} - 30^{\circ} = 45^{\circ}$.Therefore, the prism angle is $45^{\circ}$.

The figure shows the graph of the angle of deviation $\delta$ versus the angle of incidence $i$ for a light ray striking a prism. The prism angle $A$ is: (in $^{\circ}$)

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