The figure shows the variation of photocurren | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the photoelectric effect,the stopping potential depends only on the frequency of the incident radiation and the work function of the metal surf

Vedclass · Accepted Answer

$f_a = f_b = f_c = f_d$ and $I_a < I_b < I_c < I_d$

Vedclass · Answer

(C) In the photoelectric effect,the stopping potential depends only on the frequency of the incident radiation and the work function of the metal surface. Since all four curves intersect the potential axis at the same point (the same stopping potential),the frequency of all four radiations must be the same. Therefore,$f_a = f_b = f_c = f_d$.The saturation photocurrent is directly proportional to the intensity of the incident radiation. From the graph,the saturation current values are $I_a < I_b < I_c < I_d$. Therefore,the intensities follow the same order: $I_a < I_b < I_c < I_d$.

The figure shows the variation of photocurrent with anode potential for four different radiations. Let $I_a, I_b, I_c$ and $I_d$ be the intensities for the curves $a, b, c$ and $d$ respectively $[f_a, f_b, f_c$ and $f_d$ are frequencies respectively].

Similar Questions

Which phenomena can be explained by using the particle nature of light?

Light of a certain frequency and intensity incident on a photosensitive material causes the photoelectric effect. If both the frequency and intensity are doubled,the photoelectric saturation current becomes

Threshold frequency for a metal is $15 \times 10^{14} \,Hz$. The light of wavelength $6000 \text{ Å}$ falls on the metal surface. Which one of the following statements is correct? [velocity of light, $c = 3 \times 10^{8} \,m/s$]

The electrons are emitted in the photoelectric effect from a metal surface:

Vedclass Test Series

Exam Paper Generator

Online Exam Module