(C) The ionisation potential $(IP)$ generally decreases as we move down a group in the periodic table due to the increase in atomic size and shielding

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(C) The ionisation potential $(IP)$ generally decreases as we move down a group in the periodic table due to the increase in atomic size and shielding effect.$Na$ and $K$ both belong to Group $1$ (alkali metals).Since $K$ is below $Na$ in the periodic table,the $IP$ of $K$ must be lower than the $IP$ of $Na$.The $IP$ of $Na$ is $5.14 \ eV$.Among the given options,only $4.3 \ eV$ is less than $5.14 \ eV$.Therefore,the correct option is $C$.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Ionisation energy

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The first ionisation potential $(IP)$ of the elements $Na$,$Mg$,$Si$,$P$,$Cl$ and $Ar$ are $5.14$,$7.65$,$8.15$,$10.49$,$12.97$ and $15.76 \ eV$,respectively. The $IP$ (in $eV$) of $K$ is closest to

KVPY 2020 All KVPY

A
$18.3$
B
$18.2$
C
$4.3$
D
$6.4$

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Class 11

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Chapter

Classification of Elements and Periodicity in Properties

Subtopic

Ionisation energy

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The first ionisation potential $(IP)$ of the elements $Na$,$Mg$,$Si$,$P$,$Cl$ and $Ar$ are $5.14$,$7.65$,$8.15$,$10.49$,$12.97$ and $15.76 \ eV$,respectively. The $IP$ (in $eV$) of $K$ is closest to

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