The first ionization potentials in electron v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electronic configuration of Nitrogen $(N)$ is $1s^2 2s^2 2p^3$,which has a stable half-filled $p$-orbital.The electronic configuration of Oxyg

Vedclass · Accepted Answer

$14.6, 13.6$

Vedclass · Answer

(A) The electronic configuration of Nitrogen $(N)$ is $1s^2 2s^2 2p^3$,which has a stable half-filled $p$-orbital.The electronic configuration of Oxygen $(O)$ is $1s^2 2s^2 2p^4$.Due to the extra stability of the half-filled $2p$ subshell in Nitrogen,it requires more energy to remove an electron compared to Oxygen.Therefore,the first ionization potential of Nitrogen $(14.6 \ eV)$ is higher than that of Oxygen $(13.6 \ eV)$.

The first ionization potentials in electron volts $(eV)$ of nitrogen and oxygen atoms are respectively given by:

Similar Questions

The correct order of second ionization potential of carbon,nitrogen,oxygen and fluorine is

Which of the following elements has the highest second ionisation potential?

The ionization potential of sodium is $5.48 \ eV$. The $I.P.$ of potassium is ............. $eV$

Which one of the following elements has the highest ionisation energy?

The correct order of second $I.E.$ of $C$,$N$,$O$,and $F$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module