The Fischer projection formula of L-(-)-gluco | vedclass

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Question

(D) The $D$ and $L$ configuration of monosaccharides is determined by the position of the $-OH$ group on the chiral carbon furthest from the carbonyl

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(D) The $D$ and $L$ configuration of monosaccharides is determined by the position of the $-OH$ group on the chiral carbon furthest from the carbonyl group (the $C-5$ carbon in glucose). However,the question asks for the enantiomer of $D-(+)-glucose$,which is $L-(-)-glucose$. In $D-(+)-glucose$,the $-OH$ groups are at positions: $C-2$ (right),$C-3$ (left),$C-4$ (right),and $C-5$ (right). In $L-(-)-glucose$,the configuration at every chiral center is inverted compared to $D-glucose$. Therefore,in $L-(-)-glucose$,the $-OH$ groups are at positions: $C-2$ (left),$C-3$ (right),$C-4$ (left),and $C-5$ (left). This corresponds to the structure shown in option $D$.

The Fischer projection formula of $L-(-)-glucose$ is:

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