The flocculation value of HCl for arsenic sul | vedclass

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Question

(A) The flocculation value depends on the coagulating ion. For a negatively charged arsenic sulphide sol,the coagulating ion is the cation $(H^+)$.$1

Vedclass · Accepted Answer

$0.37$

Vedclass · Answer

(A) The flocculation value depends on the coagulating ion. For a negatively charged arsenic sulphide sol,the coagulating ion is the cation $(H^+)$.$1 \; mol$ of $H_{2}SO_{4}$ provides $2 \; mol$ of $H^+$ ions,whereas $1 \; mol$ of $HCl$ provides $1 \; mol$ of $H^+$ ions.Therefore,the flocculation value of $H_{2}SO_{4}$ is half that of $HCl$,which is $15 \; mmol \; L^{-1}$.For $250 \; mL$ $(0.25 \; L)$ of sol,the required amount of $H_{2}SO_{4}$ is $15 \; mmol/L 	imes 0.25 \; L = 3.75 \; mmol$.Mass of $H_{2}SO_{4} = 	ext{moles} 	imes 	ext{molar mass} = 3.75 	imes 10^{-3} \; mol 	imes 98 \; g/mol = 0.3675 \; g$.Rounding to two decimal places,we get $0.37 \; g$.

The flocculation value of $HCl$ for arsenic sulphide sol is $30 \; mmol \; L^{-1}$. If $H_{2}SO_{4}$ is used for the flocculation of arsenic sulphide,the amount,in grams,of $H_{2}SO_{4}$ in $250 \; mL$ required for the above purpose is (molecular mass of $H_{2}SO_{4} = 98 \; g/mol$)

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