The fluorine molecule is formed by
- A$p-p$ orbitals (sideways overlap)
- B$p-p$ orbitals (end-to-end overlap)
- C$sp-sp$ orbitals
- D$s-s$ orbitals
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Similar Questions
Determine the number of sigma $(\sigma)$ and pi $(\pi)$ bonds in the following molecules: $(i)$ Methane,$(ii)$ Ethane,$(iii)$ Ethene,$(iv)$ Ethyne.
Medium
View SolutionWhich of the following combinations does not form a $\sigma$ bond?
$(i) \ 2p_y - 2p_y$
$(ii) \ 2p_z - 2p_z$
$(iii) \ 2s - 2p_x$
$(iv) \ 2p_x - 2p_x$
$(i) \ 2p_y - 2p_y$
$(ii) \ 2p_z - 2p_z$
$(iii) \ 2s - 2p_x$
$(iv) \ 2p_x - 2p_x$
Easy
View SolutionThe bond in the formation of fluorine molecule will be
Medium
View SolutionWhat type of bond and type of overlapping are present in the $N_2$ molecule?
What are the number of $\sigma$ and $\pi$ bonds in a sulfuric acid molecule,respectively?
Easy
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