The focal length of a convex lens will be max | vedclass

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(D) The focal length $f$ of a lens is related to the refractive index $\mu$ of the material by the Lens Maker's Formula: $\frac{1}{f} = (\mu - 1) \lef

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red light.

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(D) The focal length $f$ of a lens is related to the refractive index $\mu$ of the material by the Lens Maker's Formula: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.From this formula,it is clear that $f \propto \frac{1}{\mu - 1}$.According to Cauchy's equation,the refractive index $\mu$ is inversely proportional to the square of the wavelength $\lambda$ $(\mu \approx A + \frac{B}{\lambda^2})$.Therefore,as the wavelength $\lambda$ increases,the refractive index $\mu$ decreases.Among the given colors,red light has the maximum wavelength $(\lambda_{red} > \lambda_{yellow} > \lambda_{blue} > \lambda_{violet})$.Since red light has the longest wavelength,it has the minimum refractive index $\mu$ for the lens material.Consequently,the focal length $f$ will be maximum for red light.

The focal length of a convex lens will be maximum for:

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