The following equilibrium constants are given | vedclass

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(A) Given reactions:$(i) N_2 + 3 H_2 \rightleftharpoons 2 NH_3 ; k_1$$(ii) N_2 + O_2 \rightleftharpoons 2 NO ; k_2$$(iii) H_2 + 1/2 O_2 \rightleftharp

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$\frac{k_2^{1/2} k_3^{3/2}}{k_1^{1/2}}$

Vedclass · Answer

(A) Given reactions:$(i) N_2 + 3 H_2 ightleftharpoons 2 NH_3 ; k_1$$(ii) N_2 + O_2 ightleftharpoons 2 NO ; k_2$$(iii) H_2 + 1/2 O_2 ightleftharpoons H_2 O ; k_3$Target reaction: $NH_3 + 5/4 O_2 ightleftharpoons NO + 3/2 H_2 O$To obtain the target reaction,we perform the following operations:$1/2 	imes (ii) + 3/2 	imes (iii) - 1/2 	imes (i)$$1/2 (N_2 + O_2 ightleftharpoons 2 NO) \Rightarrow 1/2 N_2 + 1/2 O_2 ightleftharpoons NO$ $(k_2^{1/2})$$3/2 (H_2 + 1/2 O_2 ightleftharpoons H_2 O) \Rightarrow 3/2 H_2 + 3/4 O_2 ightleftharpoons 3/2 H_2 O$ $(k_3^{3/2})$$-1/2 (N_2 + 3 H_2 ightleftharpoons 2 NH_3) \Rightarrow NH_3 ightleftharpoons 1/2 N_2 + 3/2 H_2$ $(k_1^{-1/2})$Adding these gives: $NH_3 + 5/4 O_2 ightleftharpoons NO + 3/2 H_2 O$The equilibrium constant $K = \frac{k_2^{1/2} 	imes k_3^{3/2}}{k_1^{1/2}}$.

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