(B) According to Le Chatelier's principle,adding $HCl$ increases the concentration of $H^{+}$ ions in the solution.This shift in concentration causes

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Concentration of $CH_3COO^{-}$ will decrease

(B) According to Le Chatelier's principle,adding $HCl$ increases the concentration of $H^{+}$ ions in the solution.This shift in concentration causes the equilibrium to move in the reverse direction to counteract the change.As the reaction proceeds in the reverse direction,the concentration of $CH_3COO^{-}$ ions will decrease.The equilibrium constant $(K_a)$ remains unchanged because the temperature is constant.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Common ion effect

Easy

The following equilibrium exists in aqueous solution: $CH_3COOH \rightleftharpoons CH_3COO^{-} + H^{+}$. If dilute $HCl$ is added without a change in temperature,then the:

A
Concentration of $CH_3COO^{-}$ will increase
B
Concentration of $CH_3COO^{-}$ will decrease
C
Equilibrium constant will increase
D
Equilibrium constant will decrease

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6-2.Equilibrium-II (Ionic Equilibrium)

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Common ion effect

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When $H_2S$ gas is passed into a certain solution,it reacts to form a white precipitate. The solution referred to contains ions of

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When sodium acetate is added to an acetic acid solution,the $pH$ of the solution will . . . . . . .

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The following equilibrium exists in aqueous solution: $CH_3COOH \rightleftharpoons CH_3COO^{-} + H^{+}$. If dilute $HCl$ is added without a change in temperature,then the:

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On passing $H_2S$ gas through a highly acidic solution containing $Cd^{2+}$ ions,$CdS$ is not precipitated because

Assertion : $Sb(III)$ is not precipitated as sulphide when $H_2S$ is passed through its alkaline solution.Reason : The concentration of $S^{2-}$ ion in alkaline medium is inadequate for precipitation.

The following equilibrium exists in an aqueous solution of hydrogen sulphide: $H_2S \rightleftharpoons H^{+} + HS^{-}$. If dilute $HCl$ is added to an aqueous solution of $H_2S$ without any change in temperature,what happens?

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Assertion : $Sb(III)$ is not precipitated as sulphide when $H_2S$ is passed through its alkaline solution.
Reason : The concentration of $S^{2-}$ ion in alkaline medium is inadequate for precipitation.