(N/A) The average rate of reaction is given by $r_{av} = -\frac{\Delta[C_4H_9Cl]}{\Delta t}$. Time interval $(s)$ $r_{av}$ $(mol \, L^{-1} \, s

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(N/A) The average rate of reaction is given by $r_{av} = -\frac{\Delta[C_4H_9Cl]}{\Delta t}$. Time interval $(s)$ $r_{av}$ $(mol \, L^{-1} \, s^{-1})$ $0-100$ $1.8 \times 10^{-4}$ $100-200$ $1.5 \times 10^{-4}$ $200-300$ $1.2 \times 10^{-4}$ $300-400$ $1.1 \times 10^{-4}$ $400-700$ $7.7 \times 10^{-5}$ $700-800$ $4.0 \times 10^{-5}$

Class 12 Chemistry Chemical Kinetics Rate of a reaction

Medium

The following results are obtained in the hydrolysis of chlorobutane $(C_4H_9Cl)$:

Time $(s)$ $0$ $100$ $200$ $300$ $400$ $700$ $800$

$[C_4H_9Cl]$ $(mol \, L^{-1})$ $0.100$ $0.082$ $0.067$ $0.055$ $0.044$ $0.021$ $0.017$

Calculate the average rate $r_{av}$ of the reaction during different time intervals.

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Solution

(N/A) The average rate of reaction is given by $r_{av} = -\frac{\Delta[C_4H_9Cl]}{\Delta t}$.

Time interval $(s)$	$r_{av}$ $(mol \, L^{-1} \, s^{-1})$
$0-100$	$1.8 \times 10^{-4}$
$100-200$	$1.5 \times 10^{-4}$
$200-300$	$1.2 \times 10^{-4}$
$300-400$	$1.1 \times 10^{-4}$
$400-700$	$7.7 \times 10^{-5}$
$700-800$	$4.0 \times 10^{-5}$

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Chemical Kinetics

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Rate of a reaction

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Time $(s)$	$0$	$100$	$200$	$300$	$400$	$700$	$800$
$[C_4H_9Cl]$ $(mol \, L^{-1})$	$0.100$	$0.082$	$0.067$	$0.055$	$0.044$	$0.021$	$0.017$

Similar Questions

In the hydrogenation of ethene at $298 \, K$,the number of moles of hydrogen decreases from $2.2$ to $1.4$ in $50 \, min$. Calculate the rate of reaction in units of $mol \, s^{-1}$.

For the reaction $I_2 + 2S_2O_3^{2-} \rightarrow 2I^{-} + S_4O_6^{2-}$,which of the following expressions correctly represents the rate of reaction?

For the reaction $R \rightarrow P$,the concentration of a reactant changes from $0.03 \, M$ to $0.02 \, M$ in $25 \, minutes$. Calculate the average rate of reaction using units of time both in $minutes$ and $seconds$.

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