The formal charges of C and O atoms in CO_2 ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The formal charge $(FC)$ is calculated using the formula: $FC = V - L - \frac{1}{2} B$,where $V$ is the number of valence electrons,$L$ is the num

Vedclass · Accepted Answer

$0, 0$

Vedclass · Answer

(D) The formal charge $(FC)$ is calculated using the formula: $FC = V - L - \frac{1}{2} B$,where $V$ is the number of valence electrons,$L$ is the number of lone pair electrons,and $B$ is the number of bonding electrons.For the $CO_2$ molecule with the structure $\ddot{O}=C=\ddot{O}$:For the $O$ atom: $V = 6$,$L = 4$,$B = 4$. Thus,$FC = 6 - 4 - \frac{1}{2}(4) = 0$.For the $C$ atom: $V = 4$,$L = 0$,$B = 8$. Thus,$FC = 4 - 0 - \frac{1}{2}(8) = 0$.Therefore,the formal charges of $C$ and $O$ atoms are $0$ and $0$,respectively.

The formal charges of $C$ and $O$ atoms in $CO_2$ $(\ddot{O}=C=\ddot{O})$ are,respectively:

Similar Questions

The angular shape of the ozone molecule consists of

Which one of the following is not correct for the reaction given below:
$NH_3 + BF_3 \to NH_3.BF_3$

Compound $X$ is the anhydride of sulphuric acid. The number of $\sigma$-bonds and the number of $\pi$-bonds present in $X$ are,respectively:

The decreasing order of $C-C$ bond length is:
$I.$ $C_2H_4$ $II.$ $C_2H_2$
$III.$ $C_6H_6$ $IV.$ $C_2H_6$

The angular shape of ozone molecule $(O_3)$ consists of

Vedclass Test Series

Exam Paper Generator

Online Exam Module