The formation of $PH_4^+$ is difficult compared to $NH_4^+$ because

  • A
    lone pair of phosphorus is optically inert
  • B
    lone pair of phosphorus resides in almost pure $p-$ orbital
  • C
    lone pair of phosphorus resides at $sp^3$ orbital
  • D
    lone pair of phosphorus resides in almost pure $s-$ orbital

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