The formula of nickel oxide is Ni_{0.98}O_{1. | vedclass

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(C) Let there be $100$ formula units of $Ni_{0.98}O_{1.00}$. Thus,for $100$ $O^{2-}$ ions,there are $98$ nickel ions ($Ni^{2+}$ or $Ni^{3+}$). Let $x$

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$96$

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(C) Let there be $100$ formula units of $Ni_{0.98}O_{1.00}$. Thus,for $100$ $O^{2-}$ ions,there are $98$ nickel ions ($Ni^{2+}$ or $Ni^{3+}$). Let $x$ be the number of $Ni^{2+}$ ions. Then,the number of $Ni^{3+}$ ions is $(98 - x)$. For the compound to be electrically neutral,the total positive charge must equal the total negative charge: $2x + 3(98 - x) + 100(-2) = 0$ $2x + 294 - 3x - 200 = 0$ $-x + 94 = 0$ $x = 94$ So,the number of $Ni^{2+}$ ions is $94$. The percentage of $Ni^{2+}$ ions is $\frac{94}{98} 	imes 100 \approx 95.92\%$,which is approximately $96\%$.

The formula of nickel oxide is $Ni_{0.98}O_{1.00}$. What is the approximate percentage of $Ni^{2+}$ in it?

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