The formulae of ammonium phosphomolybdate $(X)$ and the compound $(Y)$ responsible for Prussian blue colour are:

  • A
    $X: (NH_4)_3PO_4 \cdot 12MoO_3, Y: Fe_4[Fe(CN)_6]_3 \cdot xH_2O$
  • B
    $X: (NH_4)_3PO_3 \cdot 12MoO_3, Y: Fe_4[Fe(CN)_6]_3 \cdot xH_2O$
  • C
    $X: (NH_4)_2PO_3 \cdot 12MoO_3, Y: Fe_3[Fe(CN)_6]_2 \cdot xH_2O$
  • D
    $X: (NH_4)_3PO_4 \cdot 12MoO_3, Y: Fe_3[Fe(CN)_5]_2 \cdot xH_2O$

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