The four quantum numbers for the valence shel | vedclass

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Question

(B) The electronic configuration of Sodium $(Z=11)$ is $1s^2, 2s^2, 2p^6, 3s^1$. The valence shell electron is in the $3s$ orbital. For the $3s$ orbit

Vedclass · Accepted Answer

$n=3, \ell=0, m=0, s=+\frac{1}{2}$

Vedclass · Answer

(B) The electronic configuration of Sodium $(Z=11)$ is $1s^2, 2s^2, 2p^6, 3s^1$. The valence shell electron is in the $3s$ orbital. For the $3s$ orbital,the principal quantum number $n = 3$. For an $s$-orbital,the azimuthal quantum number $\ell = 0$. Since $\ell = 0$,the magnetic quantum number $m = 0$. The spin quantum number $s$ for the first electron in an orbital is typically taken as $+\frac{1}{2}$.

List-$I$ (Quantum number)	List-$II$ (Orbital)
$a. n=2, \ell=1$	$i. 2s$
$b. n=3, \ell=2$	$ii. 3s$
$c. n=3, \ell=0$	$iii. 2p$
$d. n=2, \ell=0$	$iv. 3d$

The four quantum numbers for the valence shell electron of Sodium $(Z=11)$ are:

Similar Questions

$A$ completely filled $d$ orbital $(d^{10})$ configuration is:

Match List-$I$ with List-$II$ :
List-$I$ (Quantum number) List-$II$ (Orbital)
$a. n=2, \ell=1$ $i. 2s$
$b. n=3, \ell=2$ $ii. 3s$
$c. n=3, \ell=0$ $iii. 2p$
$d. n=2, \ell=0$ $iv. 3d$

Choose the correct answer from the options given below :

For which of the following orbitals is the value of $(n + l)$ maximum?

The orbital angular momentum of an electron in a $d$ orbital is equal to:

An electron has a magnetic quantum number of $-3$. Its principal quantum number can be

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